Rational Numbers Class 7 Extra Questions Maths Chapter 9
Extra Questions for Class 7 Maths Chapter 9 Rational Numbers
Rational Numbers Class 7 Extra Questions Very Short Answer Type
Question 1.
Find three rational numbers equivalent to each of the following rational numbers.
(i) \(\frac { -2 }{ 5 }\)
(ii) \(\frac { 3 }{ 7 }\)
Solution:
Question 2.
Reduce the following rational numbers in standard form.
(i) \(\frac { 35 }{ -15 }\)
(ii) \(\frac { -36 }{ -216 }\)
Solution:
Question 3.
Represent \(\frac { 3 }{ 2 }\) and \(\frac { -3 }{ 4 }\) on number lines.
Solution:
Question 4.
Which of the following rational numbers is greater?
(i) \(\frac { 3 }{ 4 }\), \(\frac { 1 }{ 2 }\)
(ii) \(\frac { -3 }{ 2 }\), \(\frac { -3 }{ 4 }\)
Solution:
Question 5.
Find the sum of
Solution:
Question 6.
Subtract:
Solution:
Question 7.
Find the product:
Solution:
Rational Numbers Class 7 Extra Questions Short Answer Type
Question 8.
If the product of two rational numbers is \(\frac { -9 }{ 16 }\) and one of them is \(\frac { -4 }{ 15 }\), find the other number.
Solution:
Let the required rational number be x.
Question 9.
Arrange the following rational numbers in ascending order.
Solution:
Question 10.
Insert five rational numbers between:
Solution:
Rational Numbers Class 7 Extra Questions Long Answer Type
Question 11.
Evaluate the following:
Solution:
Question 12.
Subtract the sum of \(\frac { -5 }{ 6 }\) and -1\(\frac { 3 }{ 5 }\) from the sum 2\(\frac { 2 }{ 3 }\) and -6\(\frac { 2 }{ 5 }\).
Solution:
Question 13.
Solution:
We have
Question 14.
Divide the sum of -2\(\frac { 15 }{ 17 }\) and 3\(\frac { 5 }{ 34 }\) by their difference.
Solution:
Question 15.
During a festival sale, the cost of an object is ₹ 870 on which 20% is off. The same object is available at other shops for ₹ 975 with a discount of 6\(\frac { 2 }{ 3 }\) %. Which is a better deal and by how much?
Solution:
The cost of the object = ₹ 870
Discount = 20% of ₹ 870 = \(\frac { 20 }{ 100 }\) × 870 = ₹ 174
Selling price = ₹ 870 – ₹ 174 = ₹ 696
The same object is available at other shop = ₹ 975
Selling price = ₹ 975 – ₹ 65 = ₹ 910
Since ₹ 910 > ₹ 696
Hence, deal at first shop is better and by ₹ 910 – ₹ 696 = ₹ 214
Rational Numbers Class 7 Extra Questions Higher Order Thinking Skills (HOTS) Type
Question 16.
Simplify:
21.5 ÷ 5 – \(\frac { 1 }{ 5 }\) of (20.5 – 5.5) + 0.5 × 8.5
Solution:
Using BODMAS rule, we have
21.5 ÷ 5 – \(\frac { 1 }{ 5 }\) of (20.5 – 5.5) + 0.5 × 8.5
= 21.5 ÷ 5 – \(\frac { 1 }{ 5 }\) of 15 + 0.5 × 8.5
= 21.5 × \(\frac { 1 }{ 5 }\) – \(\frac { 1 }{ 5 }\) × 15 + 0.5 × 8.5
= 4.3 – 3 + 4.25
= 4.3 + 4.25 – 3
= 8.55 – 3
= 5.55
Question 17.
Simplify:
Solution:
Using BODMAS rule, we have
2.3 – [1.89 – {3.6 – (2.7 – 0.77)}]
= 2.3 – [1.89 – {3.6 – 1.93}]
= 2.3 – [1.89 – 1.67]
= 2.3 – 0.22
= 2.08
Question 18.
Solution:
Using BODMAS rule, we have
